J2SE. REST Web service access

Access Twitter api using Apache commons HTTPclient -- http://hc.apache.org/

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import org.apache.commons.httpclient.*;
import org.apache.commons.httpclient.methods.*;
import org.apache.commons.httpclient.params.HttpMethodParams;
import org.apache.commons.logging.*;

import java.io.*;

public class CallWS {

//private static String url = "http://www.apache.org/";
private static String url = "http://api.twitter.com/1/trends/current.json";

public static void main(String[] args) {
// Create an instance of HttpClient.
HttpClient client = new HttpClient();

// Create a method instance.
GetMethod method = new GetMethod(url);

// Provide custom retry handler is necessary
method.getParams().setParameter(HttpMethodParams.RETRY_HANDLER,
new DefaultHttpMethodRetryHandler(3, false));

try {
// Execute the method.
int statusCode = client.executeMethod(method);

if (statusCode != HttpStatus.SC_OK) {
System.err.println("Method failed: " + method.getStatusLine());
}

// Read the response body.
byte[] responseBody = method.getResponseBody();

// Deal with the response.
// Use caution: ensure correct character encoding and is not binary data
System.out.println(new String(responseBody));

} catch (HttpException e) {
System.err.println("Fatal protocol violation: " + e.getMessage());
e.printStackTrace();
} catch (IOException e) {
System.err.println("Fatal transport error: " + e.getMessage());
e.printStackTrace();
} finally {
// Release the connection.
method.releaseConnection();
}
}
}
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